Differential Equations...
Okay, I need help figuring out how to do this problem. I'm not simply asking for the answer because I know good and well that it won't help come test time... Here's the problem...
dT/du= -12u5, T(0)=3
Do I find the integral then plug in the three? I'm so lost...
TOLERANCE - Within reason...
Re: Differential Equations...
You're pretty much right. If you remember that an integral is the opposite of a derivative, you can integrate both sides of the equation.
Then you can use your given value to solve for the c value of the equation you get when you integrate.
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